Solubility of ionic compounds - Entropy: how far?

Solubility of ionic compounds

When an ionic solid dissolves, the following must take place:

STEP 1: The ionic lattice breaks; ions are separated.

For example:                      NaCl (s) → Na+ (g) + Cl- (g)   ΔH positive
Note that the reaction above is the reverse reaction of:
Na+ (g) + Cl- (g) → NaCl (s) where ΔH negative = ΔH lattice

(see link for definition of lattice energy)

Therefore, ΔH positive of the reaction at the top equals to   - ΔH lattice

STEP 2:  The positive cation forms dipole-ion forces with δ-O of the water molecules and negative anions with δ+H atoms of the water molecules. This process is called Hydration of ions, which is exothermic. (see link  for definition of enthalpy of hydration)

Hydration of ions
For example:           Na+ (g) + Cl- (g)   → Na+ (aq) + Cl- (aq)   

The above reaction is divided into two parts:
Na+ (g) + aq   → Na+ (aq)   ΔHhyd (Na+)
and
Cl- (g)  + aq → Cl- (aq)       ΔHhyd (Cl-)

On addition, the result reaction is:
 



NaCl (s) → Na+ (aq) + Cl- (aq)        OR      NaCl (s) + aq → NaCl (aq)    ΔH solution
 
Therefore  
ΔH solution =  -ΔH lattice + ΔHhyd (Na+) + ΔHhyd (Cl-)

 From this equation, it can be seen that:  

·         The more exothermic the lattice energy, the more endothermic (or less exothermic) the enthalpy of solution

·         The more exothermic either of the hydration enthalpies, the more exothermic the enthalpy of solution
 

Exothermic dissolving occurs when: the magnitude of the lattice enthalpy is less than the sum of the hydration enthalpies of the two ions.

Endothermic dissolving occurs when: the magnitude of the lattice enthalpy is greater than the sum of the hydration enthalpies of the two ions.

See the following links for more information on:


  •  Factors affecting Lattice Energy and Hydration Energy
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